{"id":18151,"date":"2024-04-11T00:53:02","date_gmt":"2024-04-11T00:53:02","guid":{"rendered":"https:\/\/soicau5067.minhngocxoso.com\/?p=18151"},"modified":"2024-04-11T00:53:02","modified_gmt":"2024-04-11T00:53:02","slug":"soi-cau-lo-la-gi-cach-choi-soi-cau-lo-moi-nhat-2024","status":"publish","type":"post","link":"https:\/\/soicaududoan.com\/soi-cau-lo-la-gi-cach-choi-soi-cau-lo-moi-nhat-2024\/","title":{"rendered":"soi c\u1ea7u l\u00f4 l\u00e0 g\u00ec? c\u00e1ch ch\u01a1i soi c\u1ea7u l\u00f4 m\u1edbi nh\u1ea5t 2024"},"content":{"rendered":"\n
C\u0169ng nh\u01b0 ng\u01b0\u1eddi m\u1edbi bi\u1ebft hay l\u1ea7n \u0111\u1ea7u ti\u00ean \u0111\u01b0\u1ee3c nghe th\u1ea5y th\u00ec s\u1ebd th\u1eafc m\u1eafc soi cau lo to l\u00e0 g\u00ec? B\u1ea1n bi\u1ebft nh\u1eefng g\u00ec v\u1ec1 soi c\u1ea7u l\u00f4 ? Sau \u0111\u00e2y xin chia s\u1ebd b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y nh\u1eb1m cung c\u1ea5p m\u1ed9t s\u1ed1 th\u00f4ng tin mang t\u00ednh ch\u1ea5t tham kh\u1ea3o v\u1ec1 c\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u00e3 \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng trong d\u00e2n gian.
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C\u1ea7u l\u00f4 l\u00e0 s\u1ef1 k\u1ebft h\u1ee3p gi\u1eefa hai v\u1ecb tr\u00ed b\u1ea5t k\u1ef3 trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1.<\/p>\n\n\n\n
V\u1eady n\u00ean Soi c\u1ea7u l\u00f4 l\u00e0 vi\u1ec7c soi x\u00e9t di\u1ec5n bi\u1ebfn c\u1ee7a vi\u1ec7c gh\u00e9p n\u1ed1i hai v\u1ecb tr\u00ed trong B\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 trong nhi\u1ec1u ng\u00e0y li\u00ean ti\u1ebfp.<\/p>\n\n\n\n
C\u00f3 bao nhi\u00eau v\u1ecb tr\u00ed khi soi c\u1ea7u l\u00f4?
C\u00e1c gi\u1ea3i \u0110\u1eb7c bi\u1ec7t I, II, III \u0111\u1ec1u c\u00f3 5 s\u1ed1, t\u1eeb \u0111\u00f3 10 gi\u1ea3i x 5 = 50 s\u1ed1.<\/p>\n\n\n\n
4 gi\u1ea3i T\u01b0 v\u00e0 6 gi\u1ea3i N\u0103m m\u1ed7i gi\u1ea3i 4 s\u1ed1, t\u1eeb \u0111\u00f3 (4+6) x 4 = 40 s\u1ed1.<\/p>\n\n\n\n
3 gi\u1ea3i 6 m\u1ed7i gi\u1ea3i c\u00f3 3 s\u1ed1, t\u1eeb \u0111\u00f3 3 \u00d7 3 = 9 s\u1ed1.<\/p>\n\n\n\n
4 gi\u1ea3i B\u1ea3y m\u1ed7i gi\u1ea3i 2 s\u1ed1, t\u1eeb \u0111\u00f3 4 \u00d7 2 = 8 s\u1ed1.<\/p>\n\n\n\n
T\u1ed5ng t\u1ea5t c\u1ea3 l\u1ea1i ta c\u00f3: 50 + 40 + 9 + 8 =107 s\u1ed1 hay 107 v\u1ecb tr\u00ed kh\u00e1c nhau<\/p>\n\n\n\n N\u00ean nh\u1edb r\u1eb1ng c\u00e1c v\u1ecb tr\u00ed kh\u00f4ng ch\u1ec9 gh\u00e9p v\u1edbi c\u00e1c v\u1ecb tr\u00ed kh\u00e1c m\u00e0 c\u00f2n c\u00f3 th\u1ec3 gh\u00e9p v\u1edbi ch\u00ednh n\u00f3 \u0111\u1ec3 t\u1ea1o ra nh\u1eefng c\u1eb7p s\u1ed1 k\u00e9p. B\u1edfi v\u1eady, ch\u00fang ta l\u1ea1i c\u00f3 th\u00eam 107 c\u1ea7u l\u00f4 l\u00e0 s\u1ed1 k\u00e9p n\u1eefa.<\/p>\n\n\n\n Ngo\u00e0i ra, c\u00f2n c\u00f3 c\u00e1ch gh\u00e9p t\u1eebng v\u1ecb tr\u00ed trong b\u1ea3ng k\u1ebft qu\u1ea3 v\u1edbi c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 \u0111\u1ec3 c\u00f3 th\u00eam 107 x10 = 1070 c\u1ea7u l\u00f4 ki\u1ec3u n\u00e0y (ki\u1ec3u gh\u00e9p n\u00e0y, trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p cho ra nh\u1eefng c\u1ea7u l\u00f4 r\u1ea5t t\u1ed1t).<\/p>\n\n\n\n N\u1eafm r\u00f5 c\u00e1c v\u1ecb tr\u00ed c\u0169ng nh\u01b0 t\u1ed5ng s\u1ed1 l\u01b0\u1ee3ng c\u1ea7u l\u00f4 c\u1ea7n soi x\u00e9t s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i c\u00f3 nh\u1eefng quy\u1ebft \u0111\u1ecbnh s\u00e1ng su\u1ed1t h\u01a1n trong qu\u00e1 tr\u00ecnh soi c\u1ea7u l\u00f4. M\u1ed9t \u0111i\u1ec1u m\u00e0 ng\u01b0\u1eddi ch\u01a1i lu\u00f4n \u00e1p d\u1ee5ng khi soi c\u1ea7u l\u00f4 l\u00e0 n\u1ebfu \u0111\u00e1nh l\u00f4 theo nh\u1eefng c\u1ea7u l\u00f4 c\u00f3 s\u1ed1 ng\u00e0y ra s\u1ed1 theo c\u1ea7u cao th\u00ec c\u01a1 h\u1ed9i \u0103n l\u00f4 s\u1ebd cao h\u01a1n vi\u1ec7c \u0111\u00e1nh theo nh\u1eefng c\u1ea7u l\u00f4 c\u00f3 s\u1ed1 ng\u00e0y ra s\u1ed1 th\u1ea5p<\/p>\n\n\n\n Hy v\u1ecdng v\u1edbi nh\u1eefng S\u1ef1 th\u1eadt \u0111\u00e3 v\u1ea1ch tr\u1ea7n th\u00ec anh em \u0111\u00e3 c\u00f3 c\u00e1i nh\u00ecn \u0111\u00fang \u0111\u1eafn h\u01a1n v\u1ec1 v\u1ea5n \u0111\u1ec1 n\u00e0y. L\u1ef1a ch\u1ecdn \u0111i ti\u1ebfp hay d\u1eebng l\u1ea1i \u0111am m\u00ea n\u00e0y? Ch\u00fac anh em may m\u1eafn v\u1edbi quy\u1ebft \u0111\u1ecbnh c\u1ee7a m\u00ecnh. <\/p>\n\r\n\r\nT\u1ed5ng s\u1ed1 c\u1ea7u l\u00f4 m\u00e0 ng\u01b0\u1eddi ch\u01a1i c\u1ea7n soi x\u00e9t trong soi cau lo<\/h4>\n\n\n\n
Theo \u0111\u1ecbnh ngh\u0129a v\u1ec1 c\u1ea7u l\u00f4, m\u1ed7i v\u1ecb tr\u00ed c\u00f3 th\u1ec3 gh\u00e9p v\u1edbi 106 v\u1ecb tr\u00ed kh\u00e1c \u0111\u1ec3 t\u1ea1o th\u00e0nh 106 c\u1ea7u l\u00f4 kh\u00e1c nhau. V\u00ec v\u1eady, t\u1ed5ng s\u1ed1 c\u1ea7u l\u00f4 gh\u00e9p 2 v\u1ecb tr\u00ed kh\u00e1c nhau = [(107!)\/(107-2)! x 2!] = 5671. M\u1ed7i c\u1ea7u l\u1ea1i c\u1ea7n soi x\u00e9t trong nhi\u1ec1u ng\u00e0y th\u00ec m\u1edbi bi\u1ebft c\u1ea7u n\u00e0o n\u00e0o hay ra nh\u1ea5t.<\/p>\n\n\n\nNh\u01b0 v\u1eady, t\u1ed5ng s\u1ed1 c\u1ea7u l\u00f4 m\u00e0 ng\u01b0\u1eddi ch\u01a1i l\u00f4 c\u1ea7n soi x\u00e9t khi soi c\u1ea7u l\u00f4 l\u00e0: 5671 + 107 + 1070 = 6848 c\u1ea7u.<\/h5>\n\n\n\n
L\u1eddi k\u1ebft<\/h2>\n\n\n\n
L\u00e0m gi\u00e0u t\u1eeb l\u00f4 \u0111\u1ec1 kh\u00f4ng ph\u1ea3i l\u00e0 chuy\u1ec7n vi\u1ec3n v\u00f4ng. C\u00e1i kh\u00f3 ch\u00ednh l\u00e0 m\u1ed7i ch\u00fang ta c\u1ea7n ph\u1ea3i ti\u1ebft ch\u1ebf b\u1ea3n th\u00e2n v\u00e0 ch\u1ecdn \u0111\u00fang \u0111\u01b0\u1eddng \u0111i.<\/p>\n\n\n\nC\u1ea6U \u0110\u1eb8P CAO C\u1ea4P<\/span><\/strong><\/h4>\r\n