{"id":18071,"date":"2024-03-17T04:40:33","date_gmt":"2024-03-17T04:40:33","guid":{"rendered":"https:\/\/soicau5067.minhngocxoso.com\/?p=18071"},"modified":"2024-03-17T04:40:33","modified_gmt":"2024-03-17T04:40:33","slug":"mach-ban-cach-tinh-xac-suat-du-doan-xo-so-chinh-xac-nhat","status":"publish","type":"post","link":"https:\/\/soicaududoan.com\/mach-ban-cach-tinh-xac-suat-du-doan-xo-so-chinh-xac-nhat\/","title":{"rendered":"m\u00e1ch b\u1ea1n c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 ch\u00ednh x\u00e1c nh\u1ea5t"},"content":{"rendered":"\n
D\u00f9 b\u1ea1n c\u00f3 d\u1ef1 \u0111o\u00e1n XSMN hay MB c\u0169ng c\u1ea7n nh\u1eefng c\u00e1ch x\u00e1c \u0111\u1ecbnh quy lu\u1eadt c\u1ea7u v\u00e0 x\u00e1c su\u1ea5t v\u1ec1 c\u1ea7u. Th\u01b0\u1eddng s\u1ed1 xu\u1ea5t hi\u1ec7n tr\u00ean nh\u1eefng t\u1edd v\u00e9 s\u1ed1 \u0111\u1ec1u tu\u00e2n theo quy lu\u1eadt xu\u1ea5t hi\u1ec7n c\u1ee7a t\u1eadp h\u1ee3p b\u1ed9 s\u1ed1 l\u1edbn. Nh\u01b0ng c\u0169ng c\u00f3 nh\u1eefng quy lu\u1eadt ri\u00eang bi\u1ec7t c\u1ee7a m\u1ed7i \u0111\u00e0i quay s\u1ed1 m\u00e0 ng\u01b0\u1eddi ch\u01a1i c\u1ea7n n\u1eafm v\u1eefng. V\u1edbi ng\u01b0\u1eddi m\u1edbi b\u1eaft \u0111\u1ea7u ch\u01a1i, ki\u1ebfn th\u1ee9c sau l\u00e0 \u0111i\u1ec1u c\u01a1 b\u1ea3n t\u1ed1i thi\u1ec3u c\u1ea7n bi\u1ebft. H\u00e3y c\u00f9ng t\u00ecm hi\u1ec3u \u0111\u1ec3 ko b\u1ecf l\u1ee1 nh\u1eefng gi\u1ea3i nh\u1ecf nh\u1ea5t k\u1ec3 c\u1ea3 l\u00e0 gi\u1ea3i t\u00e1m mi\u1ec1n nam hay gi\u1ea3i t\u00e1m mi\u1ec1n trung.<\/p>\n\n\n\n
B\u1ea1n c\u1ea7n bi\u1ebft x\u00e1c su\u1ea5t chi\u1ebfn th\u1eafng c\u1ee7a m\u1ed7i tr\u00f2 ch\u01a1i l\u00e0m c\u0103n c\u1ee9 l\u1ef1a ch\u1ecdn th\u00edch h\u1ee3p. C\u00e1c d\u1ef1 \u0111o\u00e1n XSMN c\u1ea7n c\u00f3 s\u1ef1 t\u00ednh to\u00e1n c\u1ea9n th\u1eadn v\u00e0 d\u1ef1a theo t\u1ef7 l\u1ec7 v\u1ec1 c\u1ee7a m\u1ed7i lo\u1ea1i h\u00ecnh.<\/p>\n\n\n\n
X\u00e1c su\u1ea5t tr\u00fang l\u00f4 \u00edt nh\u1ea5t 1 l\u1ea7n trong 27 l\u1ea7n quay s\u1ed1 = 1 \u2013 (X\u00e1c su\u1ea5t tr\u01b0\u1ee3t) = 1 \u2013 0,99^27 =23,7657%<\/p>\n\n\n\n
X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2<\/strong> = 100% \u2013 X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang = 100 \u2013 94,195% = 5,8%<\/p>\n\n\n\n Trong \u0111\u00f3 x\u00e1c xu\u1ea5t tr\u01b0\u1ee3t \u0111\u01b0\u1ee3c t\u00ednh = X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 2 con + X\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con = 57,957% + 36,238% = 94,195%.<\/p>\n\n\n\n X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/strong> = 100% \u2013 X\u00e1c su\u1ea5t tr\u01b0\u1ee3t = 100% \u2013 98,527% = 1,473%<\/p>\n\n\n\n Trong \u0111\u00f3 x\u00e1c su\u1ea5t tr\u01b0\u1ee3t l\u00f4 3 = X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 3 s\u1ed1 + X\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 s\u1ed1 + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 2 s\u1ed1 = 0,97^27 + 3 * 23,7675% * 0,98^27 + 3 * 5,8% * 0,99^27 = 98,527%<\/p>\n\n\n\n X\u00e1c su\u1ea5t tr\u00fang l\u00f4 = 1%<\/p>\n\n\n\n X\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 ba ch\u00e2n = 0.1%<\/p>\n\n\n\n Tr\u00fang l\u00f4 ba ch\u00e2n x\u00e1c su\u1ea5t 1- (0.999^27) = 2,67%<\/p>\n\n\n\n T\u00ednh to\u00e1n d\u1ef1 \u0111o\u00e1n XSMN x\u00e1c su\u1ea5t cao nh\u1ea5t<\/p>\n\n\n\n \u0110\u00e2y c\u0169ng l\u00e0 m\u1ed9t b\u00e0i to\u00e1n \u0111\u1eb7t ra cho m\u1ecdi ng\u01b0\u1eddi ch\u01a1i l\u00f4 gan. Li\u1ec7u r\u1eb1ng ch\u01a1i 1 con s\u1ed1 kh\u00f4ng c\u00f3 soi c\u1ea7u l\u00f4 \u0111\u1ec1<\/strong> bao l\u00e2u m\u1edbi c\u00f3 th\u1ec3 chi\u1ebfn th\u1eafng. C\u00f9ng ch\u00fang t\u00f4i t\u00ecm hi\u1ec3u nh\u00e9.<\/p>\n\n\n\n G\u1ecdi n l\u00e0 s\u1ed1 ng\u00e0y s\u1ebd d\u00e0nh chi\u1ebfn th\u1eafng \u00edt nh\u1ea5t 1 l\u1ea7n<\/p>\n\n\n\n Bi\u1ebfn c\u1ed1 A: kh\u00f4ng tr\u00fang<\/p>\n\n\n\n Bi\u1ebfn c\u1ed1 B: tr\u00fang \u00edt nh\u1ea5t 1 l\u1ea7n.<\/p>\n\n\n\n Ta c\u00f3:<\/p>\n\n\n\n X\u00e1c su\u1ea5t tr\u01b0\u1ee3t 27 s\u1ed1 P(A) = 0,99^27n<\/p>\n\n\n\n => P(B) = 1\u2212P(A) = 1\u22120,99^27n<\/p>\n\n\n\n X\u00e1c su\u1ea5t \u0111\u1ec3 tr\u00fang \u00edt nh\u1ea5t 1 l\u1ea7n c\u1ea7n x\u1ea5p s\u1ec9 100%. T\u1eeb \u0111\u00f3 c\u00f3:<\/p>\n\n\n\n P(B) > 99,99% \u21d4 0,99^27n < 1\u22120,9999 \u21d4 n > log0,99(1\u22120,9999)\/27 => n = 33,9<\/p>\n\n\n\n V\u1eady trong 34 ng\u00e0y ch\u01a1i theo c\u1ea3m t\u00ednh m\u00e0 kh\u00f4ng theo d\u1ef1 \u0111o\u00e1n XSMN b\u1ea1n s\u1ebd tr\u00fang th\u01b0\u1edfng. N\u1ebfu b\u1ea1n may m\u1eafn s\u1ebd chi\u1ebfn th\u1eafng nhanh h\u01a1n, tuy nhi\u00ean \u0111i\u1ec1u n\u00e0y kh\u00f4ng m\u1ea5y kh\u1ea3 quan.<\/p>\n\n\n\n B\u1edfi nh\u1eefng x\u00e1c su\u1ea5t chi\u1ebfn th\u1eafng t\u00ednh to\u00e1n \u1edf tr\u00ean qu\u00e1 nh\u1ecf nh\u01b0 v\u1eady m\u1edbi th\u1ea5y b\u1ea1n l\u00e0 ng\u01b0\u1eddi may m\u1eafn nh\u01b0 th\u1ebf n\u00e0o m\u1edbi c\u00f3 th\u1ec3 tr\u00fang th\u01b0\u1edfng. Tuy nhi\u00ean c\u00f3 m\u1ed9t c\u00e1ch r\u00fat ng\u1eafn th\u1eddi gian v\u00e0 ti\u1ec1n b\u1ea1c m\u00e0 v\u1eabn gi\u00fap b\u1ea1n chi\u1ebfn th\u1eafng \u0111\u00f3 l\u00e0 tham gia soi c\u1ea7u v\u1edbi ch\u00fang t\u00f4i. B\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c nh\u1eefng d\u1ef1 \u0111o\u00e1n ch\u00ednh x\u00e1c nh\u1ea5t, t\u1ef7 l\u1ec7 chi\u1ebfn th\u1eafng cao nh\u1ea5t. C\u00f2n ch\u1ea7n ch\u1eeb g\u00ec kh\u00f4ng li\u00ean h\u1ec7 ngay t\u1edbi ch\u00fang t\u00f4i. B\u1ea1n s\u1ebd tr\u1edf th\u00e0nh ng\u01b0\u1eddi may m\u1eafn ngay h\u00f4m nay.<\/p>\n\r\n\r\nNu\u00f4i s\u1ed1 trong bao l\u00e2u chi\u1ebfn th\u1eafng 100%<\/h2>\n\n\n\n
C\u1ea6U \u0110\u1eb8P CAO C\u1ea4P<\/span><\/strong><\/h4>\r\n